raden där det står:
Set g_oFile = g_oFso.CreateTextFile(UPLOAD_PATH & "" & extract_filename(g_oUpload("upload").Item("filename")))
kan vara typ:
Set g_oFile = g_oFso.CreateTextFile("vilketfilnamnduvill.fil")
2 svar · 128 visningar · startad av daniel_jn
Hej
Det här uploadscriptet hittade jag lite längre ner i detta forum.
När man laddar upp en fil så
vill jag att filnamnet ska bli
en 1 t.e.x 1.gif, 1.txt osv..
jag vet att jag kan använda mig av en variabel t.e.x U = 1
men vart nånstans i det här scriptet ska jag lägga i variablen U
<% @EnableSessionState = False %>
<% Option Explicit %>
<% Response.Expires = 0 %>
<%
Dim UPLOAD_PATH
UPLOAD_PATH = ("/home/b1580/public_html/nyheter/gamecube/bilder/")
Dim g_oFso, g_oFolder, g_oFile
Set g_oFso = Server.CreateObject("Scripting.FileSystemObject")
Set g_oFolder = g_oFso.getFolder(UPLOAD_PATH)
If (Request.ServerVariables("REQUEST_METHOD") = "POST") Then
Dim g_oUpload
Set g_oUpload = get_upload_files()
Dim fpos, fcontent
fcontent = g_oUpload("upload").Item("content")
Set g_oFile = g_oFso.CreateTextFile(UPLOAD_PATH & "" & extract_filename(g_oUpload("upload").Item("filename")))
For fpos = 1 to LenB(fcontent)
g_oFile.Write chr(AscB(MidB(fcontent, fpos, 1)))
Next
g_oFile.Close: Set g_oFile = Nothing
Response.Redirect Request.ServerVariables("SCRIPT_NAME")
End If
Response.Write "\<html\>\<body\>\<table\>"
Response.Write "\<tr\>\<td\>\<hr\>\</td\>\</tr\>"
For Each g_oFile In g_oFolder.Files
Response.Write "\<tr\>\<td\>\<a href=""files/" & g_oFile.Name & """\>" & g_oFile.name & "\</a\>\</td\>\</tr\>"
Next
Response.Write "\<tr\>\<td\>\<hr\>\</td\>\</tr\>"
Response.Write "\<tr\>\<td align=""right""\>\<form name=""frmUpload"" method=""post"" enctype=""multipart/form-data"" action=""" & Request.ServerVariables("SCRIPT_NAME") & """\>"
Response.Write "\<input type=""file"" name=""upload""\> \<input type=""submit"" value=""upload""\>\</td\>\</tr\>"
Response.Write "\</table\>\</body\>\</html\>"
%>
<%
Function get_upload_files()
Dim upload_object, request_binaries
Dim position_start, position_end
Dim boundary, boundary_pos
Set upload_object = Server.CreateObject("Scripting.Dictionary")
request_binaries = Request.BinaryRead(Request.TotalBytes)
position_start = 1
position_end = InstrB(position_start, request_binaries, get_byte_string(chr(13)))
boundary = MidB(request_binaries, position_start, (position_end - position_start))
boundary_pos = InstrB(1, request_binaries, boundary)
Do Until (boundary_pos = InstrB(request_binaries, boundary & get_byte_string("--")))
If Not(Response.IsClientConnected) Then Response.End
Dim name, pos_file
position_start = (InstrB(InstrB(boundary_pos, request_binaries, get_byte_string("Content-Disposition")), request_binaries, get_byte_string("name=")) + 6)
position_end = InstrB(position_start, request_binaries, get_byte_string(chr(34)))
name = get_string(MidB(request_binaries, position_start, (position_end - position_start)))
pos_file = InstrB(boundary_pos, request_binaries, get_byte_string("filename="))
If ((pos_file \<\> 0) AND (pos_file \< InstrB(position_end, request_binaries, boundary))) Then
upload_object.Add name, Server.CreateObject("Scripting.Dictionary")
position_start = (pos_file + 10)
position_end = InstrB(position_start, request_binaries, get_byte_string(chr(34)))
upload_object.item(name).Add "filename", get_string(MidB(request_binaries, position_start, (position_end - position_start)))
position_start = (InstrB(position_end, request_binaries, get_byte_string("Content-Type:")) + 14)
position_end = InstrB(position_start, request_binaries, get_byte_string(chr(13)))
upload_object.item(name).Add "content-type", get_string(MidB(request_binaries, position_start, (position_end - position_start)))
position_start = (position_end + 4)
position_end = InstrB(position_start, request_binaries, boundary) - 2
upload_object.item(name).Add "size", ((position_end - position_start))
upload_object.item(name).Add "content", MidB(request_binaries, position_start, (position_end - position_start))
End If
boundary_pos = InstrB(boundary_pos + LenB(boundary), request_binaries, boundary)
Loop
Set get_upload_files = upload_object
End Function
Function get_byte_string(str)
Dim cnt
For cnt = 1 to Len(str)
get_byte_string = get_byte_string & chrB(AscB(Mid(str, cnt, 1)))
Next
End Function
Function get_string(str)
Dim cnt
For cnt = 1 to LenB(str)
get_string = get_string & chr(AscB(MidB(str, cnt, 1)))
Next
End Function
Function extract_filename(filename)
extract_filename = Right(filename, Len(filename) - InStrRev(filename, "\\", -1, 1))
End Function
%>
raden där det står:
Set g_oFile = g_oFso.CreateTextFile(UPLOAD_PATH & "" & extract_filename(g_oUpload("upload").Item("filename")))
kan vara typ:
Set g_oFile = g_oFso.CreateTextFile("vilketfilnamnduvill.fil")
Hej igen
tack för svaret
nu undrar jag en till sak
Om man klickar på upload knappen utan att klicka på bläddra knappen och då formuläret är helt tomt så ska en bild på servern laddas upp till bildkatalogen på servern istället
Det här är sökvägen till den katalogen där bilden laddas upp från
("/home/user/public_html/nyheter/
Jag vet att jag kan använda mig av en if sats men är inte säker på hur jag ska göra
tacksam försvar
//Daniel
("/home/b1580/public_html/nyheter/