fick det fungera
name = UploadRequest.Item("namn").Item("Value")
filtyp = lcase(right(contentType,3))
nynamn = name & "." & filtyp
6 svar · 702 visningar · startad av nille99
jag har ett asp kod som klarar av att ladda upp fil på min server
men ibland så har filnamnet så konstiga namn, så jag vill ha en text ruta där jag kan skriva in ett nytt namn
hur gör jag?
<form method="post" action="outputfile.asp" enctype="multipart/form-data">
\<input type="file" name="blob"\>\<br\>
\<input type="text" name=namn\>\<br\>
\<input type="submit" value="Ladda upp, yo!"\>
</form>
outputfile.asp
<%
Server.ScriptTimeout = 500
Response.Expires=0
Response.Buffer = TRUE
Response.Clear
'Response.BinaryWrite(Request.BinaryRead(Request.TotalBytes))
byteCount = Request.TotalBytes
RequestBin = Request.BinaryRead(byteCount)
Dim UploadRequest
Set UploadRequest = CreateObject("Scripting.Dictionary")
BuildUploadRequest RequestBin
name = UploadRequest.Item("namn").Item("TextName")
contentType = UploadRequest.Item("blob").Item("ContentType")
filepathname = UploadRequest.Item("blob").Item("FileName")
filename = Right(filepathname,Len(filepathname)-InstrRev(filepathname,"\"))
value = UploadRequest.Item("blob").Item("Value")
filtyp = lcase(right(contentType,3))
Set ScriptObject = Server.CreateObject("Scripting.FileSystemObject")
set fso = server.createobject("scripting.filesystemobject")
set folder = fso.getFolder(server.mappath("./filer"))
pathEnd = Len(Server.mappath(Request.ServerVariables("PATH_INFO")))-14
' Set MyFile = ScriptObject.CreateTextFile(Left(Server.mappath(Request.ServerVariables("PATH_INFO")),pathEnd)&filename)
'Set MyFile = ScriptObject.CreateTextFile(Server.mappath(filename))
for each file in folder.files
if file.name = filename then
filename = "kopia" & filename
elseif file.name = "kopia" &filename then
filename = "kopia1" & filename
end if
next
Set MyFile = ScriptObject.CreateTextFile(Server.mappath("filer/" & filename))
For i = 1 to LenB(value)
MyFile.Write chr(AscB(MidB(value,i,1)))
Next
MyFile.Close
response.write "<b>Filens sökväg:</b> " & Server.mappath(filename) & "<br>"
response.write "<b>Filnamn:</b> " & filename & "<br><br>"
response.write "<b>typ:</b> " & filtyp & "<br><br>"
response.write "<b>value:</b> " & name & "<br><br>"
fick det fungera
name = UploadRequest.Item("namn").Item("Value")
filtyp = lcase(right(contentType,3))
nynamn = name & "." & filtyp
Annars har du parametrar i fso för overwrite
http://www.devguru.com/technologies/vbscript/14051.asp